Integrand size = 41, antiderivative size = 99 \[ \int (a+i a \tan (e+f x))^2 (A+B \tan (e+f x)) (c-i c \tan (e+f x))^5 \, dx=\frac {2 a^2 (i A+B) c^5 (1-i \tan (e+f x))^5}{5 f}-\frac {a^2 (i A+3 B) c^5 (1-i \tan (e+f x))^6}{6 f}+\frac {a^2 B c^5 (1-i \tan (e+f x))^7}{7 f} \]
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Time = 0.20 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.049, Rules used = {3669, 78} \[ \int (a+i a \tan (e+f x))^2 (A+B \tan (e+f x)) (c-i c \tan (e+f x))^5 \, dx=-\frac {a^2 c^5 (3 B+i A) (1-i \tan (e+f x))^6}{6 f}+\frac {2 a^2 c^5 (B+i A) (1-i \tan (e+f x))^5}{5 f}+\frac {a^2 B c^5 (1-i \tan (e+f x))^7}{7 f} \]
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Rule 78
Rule 3669
Rubi steps \begin{align*} \text {integral}& = \frac {(a c) \text {Subst}\left (\int (a+i a x) (A+B x) (c-i c x)^4 \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {(a c) \text {Subst}\left (\int \left (2 a (A-i B) (c-i c x)^4-\frac {a (A-3 i B) (c-i c x)^5}{c}-\frac {i a B (c-i c x)^6}{c^2}\right ) \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {2 a^2 (i A+B) c^5 (1-i \tan (e+f x))^5}{5 f}-\frac {a^2 (i A+3 B) c^5 (1-i \tan (e+f x))^6}{6 f}+\frac {a^2 B c^5 (1-i \tan (e+f x))^7}{7 f} \\ \end{align*}
Both result and optimal contain complex but leaf count is larger than twice the leaf count of optimal. \(270\) vs. \(2(99)=198\).
Time = 1.99 (sec) , antiderivative size = 270, normalized size of antiderivative = 2.73 \[ \int (a+i a \tan (e+f x))^2 (A+B \tan (e+f x)) (c-i c \tan (e+f x))^5 \, dx=\frac {a^2 A c^5 \tan (e+f x)}{f}-\frac {3 i a^2 A c^5 \tan ^2(e+f x)}{2 f}+\frac {a^2 B c^5 \tan ^2(e+f x)}{2 f}-\frac {2 a^2 A c^5 \tan ^3(e+f x)}{3 f}-\frac {i a^2 B c^5 \tan ^3(e+f x)}{f}-\frac {i a^2 A c^5 \tan ^4(e+f x)}{2 f}-\frac {a^2 B c^5 \tan ^4(e+f x)}{2 f}-\frac {3 a^2 A c^5 \tan ^5(e+f x)}{5 f}-\frac {2 i a^2 B c^5 \tan ^5(e+f x)}{5 f}+\frac {i a^2 A c^5 \tan ^6(e+f x)}{6 f}-\frac {a^2 B c^5 \tan ^6(e+f x)}{2 f}+\frac {i a^2 B c^5 \tan ^7(e+f x)}{7 f} \]
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Time = 0.36 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.84
method | result | size |
risch | \(\frac {32 c^{5} a^{2} \left (42 i A \,{\mathrm e}^{4 i \left (f x +e \right )}+42 B \,{\mathrm e}^{4 i \left (f x +e \right )}+49 i A \,{\mathrm e}^{2 i \left (f x +e \right )}-21 B \,{\mathrm e}^{2 i \left (f x +e \right )}+7 i A -3 B \right )}{105 f \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right )^{7}}\) | \(83\) |
derivativedivides | \(-\frac {i c^{5} a^{2} \left (-\frac {B \tan \left (f x +e \right )^{7}}{7}+\frac {\left (-3 i B -A \right ) \tan \left (f x +e \right )^{6}}{6}+\frac {\left (i A +4 i \left (i B -A \right )+6 B \right ) \tan \left (f x +e \right )^{5}}{5}+\frac {\left (-2 i B +2 A \right ) \tan \left (f x +e \right )^{4}}{4}+\frac {\left (-6 i A -4 i \left (i B -A \right )-B \right ) \tan \left (f x +e \right )^{3}}{3}+\frac {\left (i B +3 A \right ) \tan \left (f x +e \right )^{2}}{2}+i \tan \left (f x +e \right ) A \right )}{f}\) | \(147\) |
default | \(-\frac {i c^{5} a^{2} \left (-\frac {B \tan \left (f x +e \right )^{7}}{7}+\frac {\left (-3 i B -A \right ) \tan \left (f x +e \right )^{6}}{6}+\frac {\left (i A +4 i \left (i B -A \right )+6 B \right ) \tan \left (f x +e \right )^{5}}{5}+\frac {\left (-2 i B +2 A \right ) \tan \left (f x +e \right )^{4}}{4}+\frac {\left (-6 i A -4 i \left (i B -A \right )-B \right ) \tan \left (f x +e \right )^{3}}{3}+\frac {\left (i B +3 A \right ) \tan \left (f x +e \right )^{2}}{2}+i \tan \left (f x +e \right ) A \right )}{f}\) | \(147\) |
norman | \(\frac {A \,a^{2} c^{5} \tan \left (f x +e \right )}{f}-\frac {\left (-i A \,a^{2} c^{5}+3 B \,a^{2} c^{5}\right ) \tan \left (f x +e \right )^{6}}{6 f}-\frac {\left (2 i B \,a^{2} c^{5}+3 A \,a^{2} c^{5}\right ) \tan \left (f x +e \right )^{5}}{5 f}-\frac {\left (3 i B \,a^{2} c^{5}+2 A \,a^{2} c^{5}\right ) \tan \left (f x +e \right )^{3}}{3 f}+\frac {\left (-3 i A \,a^{2} c^{5}+B \,a^{2} c^{5}\right ) \tan \left (f x +e \right )^{2}}{2 f}-\frac {\left (i A \,a^{2} c^{5}+B \,a^{2} c^{5}\right ) \tan \left (f x +e \right )^{4}}{2 f}+\frac {i B \,a^{2} c^{5} \tan \left (f x +e \right )^{7}}{7 f}\) | \(203\) |
parallelrisch | \(\frac {30 i B \,a^{2} c^{5} \tan \left (f x +e \right )^{7}+35 i A \tan \left (f x +e \right )^{6} a^{2} c^{5}-84 i B \tan \left (f x +e \right )^{5} a^{2} c^{5}-105 B \tan \left (f x +e \right )^{6} a^{2} c^{5}-105 i A \tan \left (f x +e \right )^{4} a^{2} c^{5}-126 A \tan \left (f x +e \right )^{5} a^{2} c^{5}-210 i B \tan \left (f x +e \right )^{3} a^{2} c^{5}-105 B \tan \left (f x +e \right )^{4} a^{2} c^{5}-315 i A \tan \left (f x +e \right )^{2} a^{2} c^{5}-140 A \tan \left (f x +e \right )^{3} a^{2} c^{5}+105 B \tan \left (f x +e \right )^{2} a^{2} c^{5}+210 A \tan \left (f x +e \right ) a^{2} c^{5}}{210 f}\) | \(215\) |
parts | \(\frac {\left (-5 i A \,a^{2} c^{5}-B \,a^{2} c^{5}\right ) \left (\frac {\tan \left (f x +e \right )^{2}}{2}-\frac {\ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2}\right )}{f}+\frac {\left (-5 i B \,a^{2} c^{5}-5 A \,a^{2} c^{5}\right ) \left (\frac {\tan \left (f x +e \right )^{3}}{3}-\tan \left (f x +e \right )+\arctan \left (\tan \left (f x +e \right )\right )\right )}{f}+\frac {\left (-3 i A \,a^{2} c^{5}+B \,a^{2} c^{5}\right ) \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2 f}+\frac {\left (-3 i B \,a^{2} c^{5}-A \,a^{2} c^{5}\right ) \left (\tan \left (f x +e \right )-\arctan \left (\tan \left (f x +e \right )\right )\right )}{f}+\frac {\left (-i A \,a^{2} c^{5}-5 B \,a^{2} c^{5}\right ) \left (\frac {\tan \left (f x +e \right )^{4}}{4}-\frac {\tan \left (f x +e \right )^{2}}{2}+\frac {\ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2}\right )}{f}+\frac {\left (-i B \,a^{2} c^{5}-3 A \,a^{2} c^{5}\right ) \left (\frac {\tan \left (f x +e \right )^{5}}{5}-\frac {\tan \left (f x +e \right )^{3}}{3}+\tan \left (f x +e \right )-\arctan \left (\tan \left (f x +e \right )\right )\right )}{f}+\frac {\left (i A \,a^{2} c^{5}-3 B \,a^{2} c^{5}\right ) \left (\frac {\tan \left (f x +e \right )^{6}}{6}-\frac {\tan \left (f x +e \right )^{4}}{4}+\frac {\tan \left (f x +e \right )^{2}}{2}-\frac {\ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2}\right )}{f}+A \,a^{2} c^{5} x +\frac {i B \,a^{2} c^{5} \left (\frac {\tan \left (f x +e \right )^{7}}{7}-\frac {\tan \left (f x +e \right )^{5}}{5}+\frac {\tan \left (f x +e \right )^{3}}{3}-\tan \left (f x +e \right )+\arctan \left (\tan \left (f x +e \right )\right )\right )}{f}\) | \(429\) |
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Time = 0.25 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.54 \[ \int (a+i a \tan (e+f x))^2 (A+B \tan (e+f x)) (c-i c \tan (e+f x))^5 \, dx=-\frac {32 \, {\left (42 \, {\left (-i \, A - B\right )} a^{2} c^{5} e^{\left (4 i \, f x + 4 i \, e\right )} + 7 \, {\left (-7 i \, A + 3 \, B\right )} a^{2} c^{5} e^{\left (2 i \, f x + 2 i \, e\right )} + {\left (-7 i \, A + 3 \, B\right )} a^{2} c^{5}\right )}}{105 \, {\left (f e^{\left (14 i \, f x + 14 i \, e\right )} + 7 \, f e^{\left (12 i \, f x + 12 i \, e\right )} + 21 \, f e^{\left (10 i \, f x + 10 i \, e\right )} + 35 \, f e^{\left (8 i \, f x + 8 i \, e\right )} + 35 \, f e^{\left (6 i \, f x + 6 i \, e\right )} + 21 \, f e^{\left (4 i \, f x + 4 i \, e\right )} + 7 \, f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )}} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 243 vs. \(2 (80) = 160\).
Time = 0.61 (sec) , antiderivative size = 243, normalized size of antiderivative = 2.45 \[ \int (a+i a \tan (e+f x))^2 (A+B \tan (e+f x)) (c-i c \tan (e+f x))^5 \, dx=\frac {224 i A a^{2} c^{5} - 96 B a^{2} c^{5} + \left (1568 i A a^{2} c^{5} e^{2 i e} - 672 B a^{2} c^{5} e^{2 i e}\right ) e^{2 i f x} + \left (1344 i A a^{2} c^{5} e^{4 i e} + 1344 B a^{2} c^{5} e^{4 i e}\right ) e^{4 i f x}}{105 f e^{14 i e} e^{14 i f x} + 735 f e^{12 i e} e^{12 i f x} + 2205 f e^{10 i e} e^{10 i f x} + 3675 f e^{8 i e} e^{8 i f x} + 3675 f e^{6 i e} e^{6 i f x} + 2205 f e^{4 i e} e^{4 i f x} + 735 f e^{2 i e} e^{2 i f x} + 105 f} \]
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Time = 0.41 (sec) , antiderivative size = 151, normalized size of antiderivative = 1.53 \[ \int (a+i a \tan (e+f x))^2 (A+B \tan (e+f x)) (c-i c \tan (e+f x))^5 \, dx=\frac {30 i \, B a^{2} c^{5} \tan \left (f x + e\right )^{7} + 35 \, {\left (i \, A - 3 \, B\right )} a^{2} c^{5} \tan \left (f x + e\right )^{6} - 42 \, {\left (3 \, A + 2 i \, B\right )} a^{2} c^{5} \tan \left (f x + e\right )^{5} + 105 \, {\left (-i \, A - B\right )} a^{2} c^{5} \tan \left (f x + e\right )^{4} - 70 \, {\left (2 \, A + 3 i \, B\right )} a^{2} c^{5} \tan \left (f x + e\right )^{3} + 105 \, {\left (-3 i \, A + B\right )} a^{2} c^{5} \tan \left (f x + e\right )^{2} + 210 \, A a^{2} c^{5} \tan \left (f x + e\right )}{210 \, f} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 180 vs. \(2 (83) = 166\).
Time = 1.02 (sec) , antiderivative size = 180, normalized size of antiderivative = 1.82 \[ \int (a+i a \tan (e+f x))^2 (A+B \tan (e+f x)) (c-i c \tan (e+f x))^5 \, dx=-\frac {32 \, {\left (-42 i \, A a^{2} c^{5} e^{\left (4 i \, f x + 4 i \, e\right )} - 42 \, B a^{2} c^{5} e^{\left (4 i \, f x + 4 i \, e\right )} - 49 i \, A a^{2} c^{5} e^{\left (2 i \, f x + 2 i \, e\right )} + 21 \, B a^{2} c^{5} e^{\left (2 i \, f x + 2 i \, e\right )} - 7 i \, A a^{2} c^{5} + 3 \, B a^{2} c^{5}\right )}}{105 \, {\left (f e^{\left (14 i \, f x + 14 i \, e\right )} + 7 \, f e^{\left (12 i \, f x + 12 i \, e\right )} + 21 \, f e^{\left (10 i \, f x + 10 i \, e\right )} + 35 \, f e^{\left (8 i \, f x + 8 i \, e\right )} + 35 \, f e^{\left (6 i \, f x + 6 i \, e\right )} + 21 \, f e^{\left (4 i \, f x + 4 i \, e\right )} + 7 \, f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )}} \]
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Time = 9.22 (sec) , antiderivative size = 158, normalized size of antiderivative = 1.60 \[ \int (a+i a \tan (e+f x))^2 (A+B \tan (e+f x)) (c-i c \tan (e+f x))^5 \, dx=\frac {A\,a^2\,c^5\,\mathrm {tan}\left (e+f\,x\right )+\frac {a^2\,c^5\,{\mathrm {tan}\left (e+f\,x\right )}^3\,\left (-3\,B+A\,2{}\mathrm {i}\right )\,1{}\mathrm {i}}{3}+\frac {a^2\,c^5\,{\mathrm {tan}\left (e+f\,x\right )}^5\,\left (-2\,B+A\,3{}\mathrm {i}\right )\,1{}\mathrm {i}}{5}-\frac {a^2\,c^5\,{\mathrm {tan}\left (e+f\,x\right )}^2\,\left (3\,A+B\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{2}-\frac {a^2\,c^5\,{\mathrm {tan}\left (e+f\,x\right )}^4\,\left (A-B\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{2}+\frac {a^2\,c^5\,{\mathrm {tan}\left (e+f\,x\right )}^6\,\left (A+B\,3{}\mathrm {i}\right )\,1{}\mathrm {i}}{6}+\frac {B\,a^2\,c^5\,{\mathrm {tan}\left (e+f\,x\right )}^7\,1{}\mathrm {i}}{7}}{f} \]
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